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Class 9 Science: Sound Waves: Characteristics and Applications — Chapter Question Set
Chapter-wise questions and answers for Class 9 Science: Sound Waves: Characteristics and Applications — Chapter Question Set in Class 9 Science, with a clear summary, key points, and exam-ready model answers.
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About 55 min readChapter 10: Sound Waves: Characteristics and ApplicationsUpdated 15 Sep 2026
148 questions
Question 1: Sound is produced when an object:
(a) vibrates
(b) remains completely still
(c) is cooled
(d) is polished
Show answer
(a) vibrates
Question 2: The periodic to-and-fro motion of an object about its mean position is called:
(a) translation
(b) rotation
(c) circulation
(d) vibration
Show answer
(d) vibration
Question 3: In humans, sound is produced by the vibration of:
(a) the nasal cavity
(b) the lips
(c) the tongue
(d) the vocal cords
Show answer
(d) the vocal cords
Question 4: Vocal cords are located inside the:
(a) cochlea
(b) mouth cavity
(c) larynx (voice box)
(d) trachea
Show answer
(c) larynx (voice box)
Question 5: Which of these animals produces sound by rubbing its wings or legs?
(a) elephant
(b) dog
(c) bat
(d) grasshopper
Show answer
(d) grasshopper
Question 6: While performing an experiment, a tuning fork is always held by its:
(a) stem
(b) prongs
(c) U-bend
(d) rubber pad
Show answer
(a) stem
Question 7: When a prong of a vibrating tuning fork touches water, waves are seen on the surface. This shows that:
(a) water conducts electricity
(b) water is hot
(c) the prong is vibrating
(d) sound travels in vacuum
Show answer
(c) the prong is vibrating
Question 8: The material through which sound propagates is called a:
(a) source
(b) vacuum
(c) medium
(d) wavefront
Show answer
(c) medium
Question 9: Sound can propagate through:
(a) vacuum
(b) only solids
(c) solids, liquids and gases
(d) only gases
Show answer
(c) solids, liquids and gases
Question 10: In the bell jar experiment, as air is pumped out of the jar, the sound of the bell:
(a) remains the same
(b) changes pitch
(c) becomes fainter and almost inaudible
(d) becomes louder
Show answer
(c) becomes fainter and almost inaudible
Question 11: Astronauts on a spacewalk cannot hear each other directly because:
(a) they wear helmets
(b) sound travels too fast in space
(c) space is a near vacuum and sound needs a medium
(d) they are too far apart
Show answer
(c) space is a near vacuum and sound needs a medium
Question 12: In a sound wave, the particles of the medium vibrate:
(a) in circles
(b) perpendicular to the direction of propagation
(c) along random paths with the wave
(d) parallel to the direction of propagation
Show answer
(d) parallel to the direction of propagation
Question 13: Waves in which particles vibrate parallel to the direction of wave propagation are called:
(a) transverse waves
(b) electromagnetic waves
(c) seismic waves
(d) longitudinal waves
Question 15: Which of these waves can travel through a vacuum?
(a) sound
(b) seismic
(c) ultrasound
(d) light
Show answer
(d) light
Question 16: The region of the medium where density becomes higher than the average density is called a:
(a) rarefaction
(b) trough
(c) crest
(d) compression
Show answer
(d) compression
Question 17: The region of the medium with density lower than the average density is called a:
(a) compression
(b) rarefaction
(c) trough only
(d) amplitude
Show answer
(b) rarefaction
Question 18: In the propagation of a sound wave, what actually travels from the source to the listener?
(a) a stream of air
(b) the source material
(c) energy
(d) particles of the medium
Show answer
(c) energy
Question 19: A microphone converts:
(a) sound to heat
(b) light to sound
(c) electrical energy to sound energy
(d) sound energy to electrical energy
Show answer
(d) sound energy to electrical energy
Question 20: In a loudspeaker, an electrical signal makes a cone vibrate. This converts:
(a) electrical energy to sound energy
(b) chemical energy to sound
(c) sound energy to electrical energy
(d) heat to light
Show answer
(a) electrical energy to sound energy
Question 21: On a density–distance graph of a sound wave, the highest point (maximum density) is called the:
(a) node
(b) amplitude
(c) trough
(d) crest
Show answer
(d) crest
Question 22: The lowest point on the density–distance graph of a sound wave represents:
(a) minimum density
(b) zero density
(c) maximum density
(d) average density
Show answer
(a) minimum density
Question 23: The wavelength of a wave is the distance between:
(a) two consecutive crests or troughs
(b) a crest and the nearest trough
(c) two compressions only
(d) source and listener
Show answer
(a) two consecutive crests or troughs
Question 24: The SI unit of wavelength is:
(a) second
(b) metre
(c) hertz
(d) metre per second
Show answer
(b) metre
Question 25: The SI unit of frequency is:
(a) decibel
(b) metre
(c) hertz
(d) second
Show answer
(c) hertz
Question 26: The relation between time period (T) and frequency (ν) is:
(a) ν = T²
(b) ν = 1/T
(c) ν = T
(d) ν = 2T
Show answer
(b) ν = 1/T
Question 27: If there are 10 density oscillations at a point in 2 seconds, the frequency of the wave is:
(a) 5 Hz
(b) 20 Hz
(c) 10 Hz
(d) 0.2 Hz
Show answer
(a) 5 Hz
Question 28: The time period of a wave of frequency 5 Hz is:
(a) 5 s
(b) 0.5 s
(c) 0.2 s
(d) 2 s
Show answer
(c) 0.2 s
Question 29: The amplitude of a sound wave is the maximum change in:
(a) speed
(b) density compared to the average density
(c) frequency
(d) wavelength
Show answer
(b) density compared to the average density
Question 30: Compared with a wave of smaller amplitude, a sound wave of larger amplitude carries:
(a) higher pitch
(b) less energy
(c) more energy
(d) the same energy
Show answer
(c) more energy
Question 31: The amount of sound energy passing through a unit area perpendicular to the direction of propagation in unit time is called:
(a) loudness
(b) pitch
(c) amplitude
(d) intensity
Show answer
(d) intensity
Question 32: The speed of a sound wave is related to its wavelength and frequency as:
(a) v = λ/ν
(b) v = ν/λ
(c) v = λ × ν
(d) v = λ × T
Show answer
(c) v = λ × ν
Question 33: In which medium does sound travel fastest?
(a) liquids
(b) solids
(c) gases
(d) vacuum
Show answer
(b) solids
Question 34: The approximate speed of sound in air at 15 °C is:
(a) 1500 m s⁻¹
(b) 34 m s⁻¹
(c) 5000 m s⁻¹
(d) 340 m s⁻¹
Show answer
(d) 340 m s⁻¹
Question 35: Compared to its speed in air, sound travels in water about:
(a) 4–5 times slower
(b) 15–20 times faster
(c) 4–5 times faster
(d) at the same speed
Show answer
(c) 4–5 times faster
Question 36: If the temperature of the air increases, the speed of sound in it:
(a) remains constant
(b) first decreases then increases
(c) increases
(d) decreases
Show answer
(c) increases
Question 37: As the humidity of air increases, the speed of sound in air:
(a) decreases
(b) is unaffected
(c) becomes zero
(d) increases
Show answer
(d) increases
Question 38: The audible range of the human ear is:
(a) 200 Hz to 200 kHz
(b) 2 Hz to 2000 Hz
(c) 20 kHz to 200 kHz
(d) 20 Hz to 20,000 Hz
Show answer
(d) 20 Hz to 20,000 Hz
Question 39: Sound waves with frequency below 20 Hz are called:
(a) ultrasonic waves
(b) audible waves
(c) supersonic waves
(d) infrasonic waves
Show answer
(d) infrasonic waves
Question 40: Sound waves with frequency above 20 kHz are called:
(a) audible waves
(b) seismic waves
(c) ultrasonic waves
(d) infrasonic waves
Show answer
(c) ultrasonic waves
Question 41: Which animal can detect infrasonic waves?
(a) dog
(b) bat
(c) elephant
(d) dolphin
Show answer
(c) elephant
Question 42: Which of the following can detect ultrasonic waves?
(a) cow
(b) elephant
(c) human being
(d) bat
Show answer
(d) bat
Question 43: Bats search for prey in the dark using:
(a) visible light
(b) smell only
(c) infrasonic waves
(d) ultrasonic waves and echoes
Show answer
(d) ultrasonic waves and echoes
Question 44: SONAR stands for:
(a) sonic waves and rays
(b) sonic navigation and reflection
(c) sound navigation and ranging
(d) sound navigation and reflection
Show answer
(c) sound navigation and ranging
Question 45: To hear two sounds as separate sounds, the minimum time gap between them must be:
(a) 0.5 s
(b) 1 s
(c) 0.01 s
(d) 0.1 s
Show answer
(d) 0.1 s
Question 46: Taking the speed of sound as 340 m s⁻¹, the minimum distance of a reflecting surface to hear an echo is:
(a) 68 m
(b) 34 m
(c) 17 m
(d) 3.4 m
Show answer
(c) 17 m
Question 47: The persistence of sound due to multiple reflections in a large hall is called:
(a) reverberation
(b) echo
(c) resonance
(d) refraction
Show answer
(a) reverberation
Question 48: Reverberation occurs when reflected sound arrives with a time difference of about:
(a) less than 0.05 s
(b) 0.1 s to 0.2 s
(c) more than 1 s
(d) more than 0.1 s
Show answer
(a) less than 0.05 s
Question 49: The wavelength in air of a 20 Hz sound (speed of sound = 344 m s⁻¹) is about:
(a) 34.4 m
(b) 172 m
(c) 1.72 cm
(d) 17.2 m
Show answer
(d) 17.2 m
Question 50: During a thunderstorm, thunder is heard 5 s after the lightning flash is seen (speed of sound = 340 m s⁻¹). The lightning struck about:
(a) 170 m away
(b) 3400 m away
(c) 1700 m away
(d) 68 m away
Show answer
(c) 1700 m away
Question 51: A person claps and hears the echo from a wall after 0.5 s (speed of sound = 340 m s⁻¹). The distance of the wall from the person is:
(a) 85 m
(b) 42.5 m
(c) 170 m
(d) 340 m
Show answer
(a) 85 m
Question 52: A sonar signal sent into seawater returns in 0.90 s (speed in seawater = 1530 m s⁻¹). The object is at a distance of:
(a) 1377 m
(b) 344.25 m
(c) 1530 m
(d) 688.5 m
Show answer
(d) 688.5 m
Question 53: Ultrasonic waves are used in medicine for:
(a) X-ray imaging
(b) measuring blood pressure
(c) blood testing
(d) breaking kidney stones into small pieces
Show answer
(d) breaking kidney stones into small pieces
Question 54: In industries, defects hidden inside metal blocks are detected using:
(a) X-rays only
(b) microwaves
(c) ultrasonic waves
(d) infrasonic waves
Show answer
(c) ultrasonic waves
Question 55: The loudness of sound is commonly measured in:
(a) hertz
(b) watts
(c) metres
(d) decibels
Show answer
(d) decibels
Question 56: Sound is produced by the ______ of objects.
Show answer
vibration
Question 57: The material through which sound propagates is called a ______.
Show answer
medium
Question 58: Waves that require a material medium for propagation are called ______ waves.
Show answer
mechanical
Question 59: The distance between two consecutive crests or two consecutive troughs is called the ______.
Show answer
wavelength
Question 60: The SI unit of frequency is the ______.
Show answer
hertz (Hz)
Question 61: The speed of a sound wave is given by the formula v = ______.
Show answer
λ × ν (wavelength × frequency)
Question 62: Sound travels fastest in ______, slower in liquids and slowest in gases.
Show answer
solids
Question 63: Sound waves with frequency below 20 Hz are called ______ waves.
Show answer
infrasonic
Question 64: The minimum time gap needed to hear an echo distinctly is ______ second.
Show answer
0.1
Question 65: The persistence of sound due to multiple reflections in a hall is called ______.
Show answer
reverberation
Question 66: The ability of bats to locate prey using reflected ultrasonic waves is called ______.
Show answer
echolocation
Question 67: The way humans perceive the frequency of sound is called ______.
Show answer
pitch
Question 68: On a density–distance graph, the highest point of the wave is called the ______.
Show answer
crest
Question 69: The maximum change in density of a medium in a compression or rarefaction compared to the average density is the ______.
Show answer
amplitude
Question 70: Ultrasonic waves are used in ______ for imaging internal organs without surgery.
Show answer
ultrasonography
Question 71: Sound can travel through a perfect vacuum.
Show answer
False
Question 72: Sound waves are transverse waves.
Show answer
False (they are longitudinal)
Question 73: In a sound wave, the particles of the medium travel from the source to the listener.
Show answer
False (only energy travels; particles oscillate)
Question 74: Sound is a mechanical wave and needs a medium to propagate.
Show answer
True
Question 75: The loudness of a sound depends on the amplitude of the wave.
Show answer
True
Question 76: A whistle has a higher pitch than the rumble of thunder.
Show answer
True
Question 77: The speed of sound is greater in steel than in air.
Show answer
True
Question 78: The speed of sound in air decreases as the temperature rises.
Show answer
False (it increases)
Question 79: The human audible range is from 20 Hz to 20,000 Hz.
Show answer
True
Question 80: Elephants can detect ultrasonic waves.
Show answer
False (they detect infrasonic waves)
Question 81: An echo is produced by the reflection of sound from a hard surface.
Show answer
True
Question 82: Reverberation is heard when reflected sounds reach the ear within about 0.05 s of the original.
Show answer
True
Question 83: SONAR uses infrasonic waves to detect underwater objects.
Show answer
False (it uses ultrasonic waves)
Question 84: In a microphone, sound energy is converted into electrical energy.
Show answer
True
Question 85: The sound produced by a tuning fork is nearly a single-frequency tone.
Show answer
True
Question 86: A: We cannot hear the bell ringing inside a jar after most of its air is pumped out.
R: Sound requires a medium to propagate.
Show answer
(a)
Question 87: A: Compressions and rarefactions move through the medium as a sound wave passes.
R: The individual particles of the medium continuously travel forward with the wave.
Show answer
(c)
Question 88: A: Astronauts doing spacewalks communicate using special devices fitted into their spacesuits.
R: Outer space is a near vacuum and sound cannot propagate through it.
Show answer
(a)
Question 89: A: Sound travels faster in steel than in air.
R: In solids the particles are closer together, so the disturbance is transferred more quickly.
Show answer
(a)
Question 90: A: The loudness of a sound decreases as we move away from its source.
R: As sound spreads over a larger area, its intensity decreases with distance.
Show answer
(a)
Question 91: A: If the frequency of a sound wave in air is increased, the speed of the wave also increases.
R: In most media the speed of sound depends only on the medium, not on the frequency.
Show answer
(d)
Question 92: A: A clear echo can be heard easily inside a very small closed room.
R: In a small room the reflected sound reaches the ear within 0.1 s and cannot be separated from the original.
Show answer
(d)
Question 93: A: A sound wave with a larger amplitude carries more energy.
R: A larger amplitude corresponds to a larger displacement of the particles of the medium.
Show answer
(a)
Question 94: Why cannot we hear the sound of an explosion occurring on the Moon?
Show answer
The Moon has no atmosphere — it is a near vacuum — and sound requires a material medium (solid, liquid or gas) to propagate. Since there are no particles to carry the vibrations, the sound of an explosion on the Moon can never reach our ears.
Question 95: State any two ways by which vibrating parts produce sound in musical instruments. Give one example of each.
Show answer
Sound in musical instruments is produced by (i) vibrating strings, as in a sitar or guitar, (ii) vibrating air columns, as in a bansuri (flute), and (iii) vibrating membranes, as in a tabla. Any two of these, with their examples, answer the question.
Question 96: A tuning fork is struck gently on a rubber pad and its prong is touched to a water surface. What is observed and what does it prove?
Show answer
When the prong of the struck tuning fork touches the water surface, waves and splashing are seen on the water. This proves that the prongs of the tuning fork are vibrating, and since sound is always produced by vibrating bodies, it demonstrates the vibrational nature of sound.
Question 97: Define time period of a wave. A sound source completes 100 oscillations in 2 s; find its time period.
Show answer
The time period of a wave is the time taken by it to complete one full oscillation. Here, T = total time ÷ number of oscillations = 2 s ÷ 100 = 0.02 s, so the time period of the source is 0.02 seconds.
Question 98: The frequency of a tuning fork is 512 Hz. What does this mean? Find the number of oscillations it completes in one minute.
Show answer
A frequency of 512 Hz means that the tuning fork completes 512 oscillations every second. Therefore, in one minute (60 s), it completes 512 × 60 = 30,720 oscillations.
Question 99: Sound of frequency 172 Hz travels in air at 344 m s⁻¹. Calculate its wavelength.
Show answer
The wavelength is found using the relation λ = v/ν, where v is the speed of sound and ν is the frequency. Substituting the values, λ = 344/172 = 2 m, so the wavelength of the sound wave is 2 metres.
Question 100: Distinguish between loudness and intensity of sound.
Show answer
Intensity is an objective, measurable physical quantity, defined as the sound energy passing through a unit area per unit time. Loudness, in contrast, is the subjective perception of that sound by the listener and depends on the hearing ability and sensitivity of the individual's ear.
Question 101: Why is a sound wave called a mechanical wave?
Show answer
A sound wave is called a mechanical wave because it requires a material medium (solid, liquid or gas) for its propagation. The particles of the medium vibrate about their fixed positions and collide with neighbouring particles, thereby transferring the disturbance from the source to the listener.
Question 102: What is SONAR? Write its one use.
Show answer
SONAR stands for Sound Navigation and Ranging. It sends ultrasonic waves into water and analyses the reflected waves to find the distance, direction and speed of underwater objects. One use is detecting submarines and shipwrecks or measuring the depth of the ocean.
Question 103: Write two applications of ultrasonic waves in the field of medicine.
Show answer
(i) Ultrasonography uses ultrasonic waves to image internal organs without surgery, which is why it is safely used to examine unborn babies. (ii) Ultrasonic waves are also used to break kidney stones into small pieces that can pass out of the body naturally, avoiding an operation.
Question 104: Why are the ceilings of concert halls and auditoriums often curved?
Show answer
Curved ceilings reflect sound waves and spread them uniformly towards the audience seated in all parts of the hall. This improves the audibility of speech and music so that every listener hears the performance clearly.
Question 105: What is reverberation? How is it reduced in auditoriums?
Show answer
Reverberation is the persistence of sound in an enclosed space due to multiple successive reflections from its walls and ceiling. It is reduced in auditoriums by using sound-absorbing materials such as panels, curtains, upholstered chairs and other soft, porous surfaces.
Question 106: A person hears thunder 3 s after seeing the lightning flash. If the speed of sound is 340 m s⁻¹, estimate the distance of the lightning strike.
Show answer
The distance is estimated using distance = speed × time. Substituting the values, distance = 340 × 3 = 1020 m, so the lightning struck approximately 1020 metres (about 1 km) away.
Question 107: Why does a louder sound produced with a larger amplitude travel farther before dying out?
Show answer
A louder sound has a larger amplitude, which means the wave carries more energy. Because of this greater energy, the wave can spread over a larger area before its intensity falls to zero, so it travels a longer distance before dying out.
Question 108: State the laws of reflection of sound.
Show answer
The laws of reflection of sound state that (i) the direction of incidence and the direction of reflection make equal angles with the normal at the point of incidence, and (ii) the incident sound, the reflected sound and the normal at the point of incidence all lie in the same plane. These laws are identical to the laws of reflection of light.
Question 109: A wave of wavelength 0.01 m travels at 340 m s⁻¹. Find its frequency and time period.
Show answer
The frequency is found using ν = v/λ = 340/0.01 = 34,000 Hz. The time period is T = 1/ν = 1/34,000 ≈ 2.94 × 10⁻⁵ s. So the wave has a frequency of 34,000 Hz and a time period of about 2.94 × 10⁻⁵ seconds.
Question 110: Why does the sound of a clap heard through a desk (ear pressed against it) seem louder than through air?
Show answer
Sound travels faster and with less energy loss in solids than in air because the particles of a solid are closely packed and transfer the disturbance efficiently. When the ear is pressed against the desk, more sound energy reaches the ear through the dense medium, making the sound appear louder.
Question 111: Why is the sound heard over a longer distance on a humid day than on a dry day?
Show answer
On a humid day, the air contains more water vapour, which is lighter than dry air, and the speed of sound increases with humidity. The disturbance therefore travels more efficiently, allowing sound to be heard over a longer distance than on a dry day.
Question 112: How do two ears help the brain locate the direction of a sound?
Show answer
Sound reaches the two ears at slightly different times because of the distance between them. The brain compares which ear receives the sound first and uses the tiny time gap between the two signals to pinpoint the direction of the sound source.
Question 113: A sonar pulse sent to find ocean depth returns after 4 s. If sound travels at 1500 m s⁻¹ in seawater, find the depth.
Show answer
The total distance travelled by the pulse (down and back) = v × t = 1500 × 4 = 6000 m. Since this is a round trip, the depth = 6000/2 = 3000 m, so the ocean is 3000 metres deep at that point.
Question 114: How is sound produced? Explain with the help of the tuning fork activity.
Show answer
Introduction: Sound is produced whenever an object vibrates, that is, moves to and fro about its mean position.
Key Points:
1. Vibration creates sound — A stretched rubber band or a struck metal object vibrates and produces sound.
2. Tuning fork activity — A tuning fork struck on a soft rubber pad is heard when brought near the ear.
3. Water surface test — Touching a vibrating prong to water makes waves, proving the prongs vibrate. Conclusion: Sound always originates from a vibrating object, called the source of the sound.
Question 115: Explain how compressions and rarefactions are formed when sound travels through air.
Show answer
Introduction: A sound wave is a series of alternating high and low density regions travelling through a medium.
Key Points:
1. Compression formation — A forward-moving piston pushes nearby air particles together, raising density locally.
2. Rarefaction formation — A backward-moving piston lets air spread out, creating a lower density region.
3. Alternating pattern travels — Colliding particles pass the disturbance on, while particles merely oscillate about mean positions. Conclusion: The travelling series of compressions and rarefactions constitutes the sound wave.
Question 116: Describe the vacuum bell jar experiment. What does it prove?
Show answer
Introduction: The bell jar experiment demonstrates that sound needs a material medium to propagate.
Key Points:
1. Set-up — An electric bell is switched on inside a sealed glass bell jar.
2. Removing air — As a vacuum pump sucks out air, the sound becomes fainter and almost disappears.
3. Conclusion from observation — When air returns, the sound is heard again; sound cannot travel in vacuum. Conclusion: Sound propagation is impossible without a medium, proving sound is a mechanical wave.
Question 117: How can we show experimentally that sound carries energy?
Show answer
Introduction: Sound is a form of energy that can move objects even without direct contact.
Key Points:
1. Grain activity — Grains are sprinkled on a rubber sheet stretched over a container.
2. Producing loud sound — A loud sound made nearby makes the sheet vibrate and the grains jump.
3. Energy transfer — The sound wave transfers energy to the sheet, showing sound carries energy. Conclusion: Sound propagates energy through the medium's vibrating particles and their collisions.
Question 118: Define wavelength, frequency and time period of a sound wave. State the relation among them.
Show answer
Introduction: Three quantities describe the basic characteristics of any sound wave.
Key Points:
1. Wavelength (λ) — Distance between two consecutive crests or two consecutive troughs; SI unit is metre.
2. Frequency (ν) — Number of density oscillations per unit time at a fixed point; SI unit is hertz.
3. Time period (T) — Time taken for one complete oscillation; frequency is the reciprocal, ν = 1/T. Conclusion: These quantities are connected by v = λν, giving the speed of the wave.
Question 119: What is amplitude? How are amplitude, energy and intensity of a sound wave related?
Show answer
Introduction: The amplitude of a sound wave determines how much energy the wave carries.
Key Points:
1. Amplitude definition — Maximum change in density in a compression or rarefaction from the average density.
2. Amplitude and energy — A wave of larger amplitude carries more energy than one of smaller amplitude.
3. Intensity and distance — Energy spread over a larger area with distance, so intensity decreases away from the source. Conclusion: Striking a source harder gives larger amplitude, more energy and hence higher intensity.
Question 120: Compare the speed of sound in solids, liquids and gases. What factors affect it in air?
Show answer
Introduction: The speed of sound depends on the medium through which it travels.
Key Points:
1. Order in media — Sound travels fastest in solids, slower in liquids and slowest in gases.
2. Typical values — Approximately 5000 m s⁻¹ in steel, 1500 m s⁻¹ in water and 340 m s⁻¹ in air.
3. Air factors — Speed in air increases with temperature and with humidity of the air. Conclusion: Closer packing of particles in denser media allows faster transfer of the disturbance.
Question 121: Distinguish between pitch and loudness of sound.
Show answer
Introduction: Pitch and loudness describe how humans subjectively perceive sound.
Key Points:
1. Pitch and frequency — Higher frequency sounds are perceived as high pitch, like a whistle or siren.
2. Loudness and amplitude — Larger amplitude is perceived as louder sound, smaller amplitude as softer.
3. Subjective nature — Both depend on the listener's hearing ability, unlike measurable physical properties. Conclusion: Pitch relates to frequency, loudness relates to amplitude; together with timbre they characterise perception.
Question 122: Explain the audible range of humans. Name the waves outside this range with examples.
Show answer
Introduction: Humans can hear only a limited range of frequencies.
Key Points:
1. Audible range — From 20 Hz to 20,000 Hz; it varies with age and person.
2. Infrasonic waves — Frequencies below 20 Hz; elephants can detect them.
3. Ultrasonic waves — Frequencies above 20 kHz; dogs, bats and dolphins detect them. Conclusion: Sounds outside 20 Hz to 20 kHz exist but are inaudible to human beings.
Question 123: What is an echo? Derive the minimum distance needed to hear an echo distinctly.
Show answer
Introduction: An echo is the reflection of sound that we hear separately after the original sound.
Key Points:
1. Condition for echo — The time gap between original and reflected sound must be at least 0.1 s.
2. Distance calculation — Sound travels 340 × 0.1 = 34 m in 0.1 s from source to reflector and back.
3. Minimum distance — Half of 34 m, that is about 17 m, is the minimum reflecting distance. Conclusion: Reflecting surfaces must be at least 17 m away for a distinct echo to be heard.
Question 124: List the main applications of ultrasonic waves in science, medicine and industry.
Show answer
Introduction: Ultrasonic waves, being inaudible and highly directional, have many practical applications.
Key Points:
1. Medical uses — Ultrasonography images internal organs; ultrasound breaks kidney stones into pieces.
2. Industrial uses — Cleaning delicate machine parts, welding, and detecting defects inside metal blocks.
3. Detection uses — Locating objects by reflected ultrasonic waves, as in sonar for underwater objects. Conclusion: Ultrasonic waves help detect, measure and treat where ordinary methods fail.
Question 125: What is echolocation? Explain how it works in bats and how humans use it in sonar.
Show answer
Introduction: Echolocation is locating objects using reflected sound waves.
Key Points:
1. Bats' method — Bats emit short bursts of ultrasonic waves which reflect off obstacles and prey.
2. Sensing echoes — From returning echoes bats judge position, distance and shape in darkness.
3. Human adaptation (sonar) — Sonar sends ultrasonic waves into water; reflected waves reveal distance, direction and speed. Conclusion: Dolphins, whales and some birds also echolocate; humans copy the principle in sonar.
Question 126: What is reverberation? How do modern auditoriums manage it?
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Introduction: Reverberation is the persistence of sound after the source stops, due to multiple reflections.
Key Points:
1. Cause — Reflected sounds arrive within about 0.05 s and overlap with the original sound.
2. Undesirable effect — Excessive reverberation garbles speech and music in large halls.
3. Control measures — Sound-absorbing panels, upholstered chairs, curtains and porous surfaces reduce it. Conclusion: Well-designed halls balance reverberation so audiences everywhere hear clear sound.
Question 127: Draw a labelled diagram of the human ear and explain how we hear.
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Introduction: The ear converts sound energy into electrical signals that the brain interprets.
Key Points:
1. Eardrum vibration — Incoming sound makes the thin eardrum membrane vibrate.
2. Amplification — Tiny bones in the middle ear amplify these vibrations.
3. Signal conversion — The cochlea converts vibrations into electrical signals that rush to the brain. Conclusion: The brain perceives these signals as sound; two ears help locate its direction.
Question 128: The graphical representation of a sound wave shows crests 3.44 m apart. If the speed of sound is 344 m s⁻¹, find the frequency and time period of the wave. Also state the wavelength.
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Introduction: The graph of a sound wave directly gives the wavelength, from which other quantities follow.
Key Points:
1. Wavelength — Distance between consecutive crests, λ = 3.44 m.
2. Frequency — ν = v/λ = 344/3.44 = 100 Hz.
3. Time period — T = 1/ν = 1/100 = 0.01 s. Conclusion: The wave has wavelength 3.44 m, frequency 100 Hz and time period 0.01 s.
Question 129: In a science laboratory, Meena suspends an electric bell inside a glass bell jar connected to a vacuum pump. As the pump removes air from the jar, the bell's sound becomes fainter, though she can still see the hammer striking the bell.
(a) Why does the loudness of the bell decrease as air is removed? (b) What would happen if air is let back into the jar? (c) What does this experiment conclude about the nature of sound? (d) Name one place where this principle applies to communication.
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(a) As air is pumped out, fewer and fewer air particles remain to carry the disturbance, so less sound energy reaches the ear and the bell sounds fainter.
(b) If air is let back in, the sound gradually becomes as loud as before, since the medium needed to propagate it is restored.
(c) The experiment concludes that sound needs a material medium — it is a mechanical wave and cannot propagate through a vacuum.
(d) This principle applies in outer space, which is a vacuum; astronauts therefore use special radio devices fitted into their spacesuits to communicate.
Question 130: During a thunderstorm, Arjun sees a lightning flash and starts a stopwatch. He hears the thunder 5 s later. Take the speed of sound in air as 340 m s⁻¹ and the speed of light as 300,000 km s⁻¹.
(a) Why is the flash seen before the thunder is heard? (b) Calculate the distance of the lightning strike. (c) If the time delay were 10 s, would the strike be nearer or farther? (d) Why do we assume light reaches us almost instantaneously?
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(a) The flash is seen first because light travels enormously faster than sound — light reaches the eye almost instantly while sound takes several seconds to arrive.
(b) Distance = speed of sound × time delay = 340 × 5 = 1700 m, which is about 1.7 km.
(c) The strike would be farther away, because distance is directly proportional to the time delay — doubling the delay doubles the distance.
(d) The speed of light is about 300,000 km s⁻¹, so it covers 1700 m in roughly five-millionths of a second, making its travel time negligible compared with that of sound.
Question 131: Riya claps her hands in an empty corridor and hears an echo after 0.5 s. The speed of sound in air is 340 m s⁻¹. Later she repeats the same in her small bedroom and hears no echo.
(a) What is an echo?
(b) Calculate Riya's distance from the corridor wall.
(c) Why is no echo heard in the small bedroom?
(d) State the minimum time gap needed to perceive an echo.
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(a) An echo is a sound that is reflected from a surface and heard separately from the original sound.
(b) Distance = (v × t)/2 = (340 × 0.5)/2 = 85 m, since the sound travels to the wall and back in 0.5 s.
(c) In the small bedroom, the reflected sound returns in less than 0.1 s, so the brain cannot separate it from the original sound, and no echo is heard.
(d) The reflected sound must return after a minimum gap of about 0.1 s for the human ear to perceive it as a distinct echo.
Question 132: A naval ship uses sonar to detect a submarine. The sonar sends an ultrasonic pulse into seawater and detects the reflected pulse after 0.90 s. The speed of sound in seawater is 1530 m s⁻¹.
(a) Why does sonar use ultrasonic waves instead of ordinary sound? (b) Why is the echo time halved to find the one-way distance? (c) Calculate the distance of the submarine. (d) Name two other uses of this principle.
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(a) Ultrasonic waves are highly directional and can locate objects precisely by reflection, whereas ordinary audible sound spreads out and cannot pinpoint targets.
(b) The recorded time includes the pulse travelling to the submarine and back again, so it must be halved to get the one-way distance.
(c) Distance = (1530 × 0.90)/2 = 1377/2 = 688.5 m, so the submarine is about 688.5 metres away.
(d) The same principle is used to measure ocean depth and locate shipwrecks; bats also use echolocation to navigate and find prey.
Question 133: A car is fitted with an ultrasonic parking-assistance sensor. While reversing, the sensor emits 40 kHz waves that reflect off an obstacle, and the warning beep starts at 1.2 m from the obstacle. Take the speed of the waves in air as 345 m s⁻¹.
(a) Why can the driver not hear these waves directly? (b) Calculate the time the wave takes to travel to the obstacle and back. (c) How does the sensor estimate the obstacle's distance? (d) Name an animal that uses the same principle.
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(a) The 40 kHz waves lie above the upper audible limit of about 20 kHz for humans, so they are ultrasonic and cannot be heard by the driver.
(b) Time = 2d/v = (2 × 1.2)/345 ≈ 0.007 s, which is the round-trip time of the wave.
(c) The sensor measures the echo time and computes the distance using distance = (speed × time)/2, giving the distance to the obstacle.
(d) A bat uses exactly this principle — it emits ultrasonic waves and locates obstacles and prey from their echoes.
Question 134: Gunjan places her ear on a long steel fence while her friend knocks the fence 340 m away with a metal object. Using speeds of 5000 m s⁻¹ in steel and 340 m s⁻¹ in air, she notices the sound reaches her through the fence first.
(a) Calculate the time taken by sound through the fence.
(b) Calculate the time taken through air.
(c) Find the time difference.
(d) Would she hear the two sounds separately (minimum gap 0.1 s)?
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(a) Time through the steel fence = distance ÷ speed = 340/5000 = 0.068 s.
(b) Time through air = 340/340 = 1.0 s.
(c) The time difference = 1.0 − 0.068 = 0.932 s.
(d) Yes, since the gap of 0.932 s is much larger than the minimum 0.1 s needed, she hears the two sounds clearly as separate signals.
Question 135: Ayesha often listens to music through earphones at very high volume. She reads that normal conversation is about 60 dB while firecrackers can exceed 100 dB, and that even small increases in dB mean large increases in intensity.
(a) What is noise? (b) Name the unit in which loudness is commonly measured. (c) What health problems can prolonged exposure to loud sound cause? (d) Name the device that helps people with hearing loss.
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(a) Noise is unwanted or unpleasant sound that causes discomfort or disturbance to the listener.
(b) Loudness is commonly measured in the unit called the decibel (dB).
(c) Prolonged exposure to loud sound can cause hearing loss and adversely affects health, sleep and overall hearing ability.
(d) A hearing aid helps such people; it contains a microphone, an amplifier and a speaker that together make sounds louder for the ear.
Question 136: A movie shows a spacecraft exploding in outer space: the audience sees a flash of light and hears a loud bang at the same instant.
(a) What is wrong in this depiction?
(b) Give the scientific reason for your answer.
(c) How do astronauts actually communicate during a spacewalk?
(d) Which waves CAN travel through space?
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(a) The depiction is wrong because no sound of the explosion could actually be heard in space — only the flash of light would be seen.
(b) Outer space is a near vacuum, and sound is a mechanical wave that needs a material medium to travel, so it cannot propagate through space.
(c) Astronauts communicate during spacewalks through special radio devices fitted into their spacesuits, which transmit signals through space.
(d) Electromagnetic waves such as light and radio waves can travel through space because they do not require any medium.
Question 137: Using the Phyphox app, a class measures frequencies of the musical notes Sa, Re, Ga, Ma, Pa, Dha, Ni, Sa sung by their teacher. The frequency is lowest for the lower 'Sa' and increases up to the higher 'Sa', which is nearly double the lower 'Sa'.
(a) What is the relation between pitch and frequency? (b) Why does each note sound different? (c) What is the interval between two notes when one has double the frequency of the other called? (d) Name one instrument that produces nearly single-frequency sound.
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(a) Pitch is directly related to frequency — the higher the frequency of a sound, the higher is its perceived pitch.
(b) Each musical note sounds different because each note has its own characteristic frequency, which our ear perceives as a distinct pitch.
(c) The interval between two notes where one has exactly double the frequency of the other is called an octave.
(d) A tuning fork produces nearly single-frequency sound, which is why it is used as a standard reference; whistling is another example.
Question 138: Two graphs, A and B, show the variation of density with distance for two sound waves drawn on the same scale. Wave A has crests closer together and lower peaks; wave B has crests farther apart and higher peaks. Both travel at 345 m s⁻¹.
(a) Which wave has the greater wavelength? (b) Which wave has the greater amplitude and what does it imply about energy? (c) Which wave will be perceived as higher pitched? (d) Write the formula connecting speed, wavelength and frequency.
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(a) Wave B has the greater wavelength, since its crests are farther apart — the distance between two successive crests is larger.
(b) Wave B has the greater amplitude because of its higher peaks; larger amplitude means the wave carries more energy and sounds louder.
(c) Wave A will sound higher pitched, because its shorter wavelength means a higher frequency (v = λ × ν), and higher frequency is heard as higher pitch.
(d) The formula connecting the three quantities is v = λ × ν, where v is the speed, λ the wavelength and ν the frequency of the wave.
Question 139: How is sound produced, and how does it propagate through a medium?
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Introduction: Sound is a form of energy produced by vibrating objects and carried through media by travelling disturbances.
Key Points:
1. Production by vibration — Every sound originates from a vibrating object like a string, membrane or air column.
2. Human voice — Vocal cords in the larynx vibrate; tongue, lips and nasal cavity shape it into speech.
3. Propagation mechanism — Particles collide with neighbours and pass the disturbance onward without travelling themselves.
4. Compressions and rarefactions — Alternating high and low density regions move away from the vibrating source.
5. Medium requirement — Sound travels through solids, liquids and gases but never through vacuum. Conclusion: Sound is a disturbance of the medium's particles, started by a vibration and carried as energy.
Question 140: Describe the characteristics of a sound wave with the help of a graphical representation.
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Introduction: A sound wave is described by wavelength, frequency, time period and amplitude, all seen on a density–distance graph.
Key Points:
1. Wavelength (λ) — Distance between two consecutive crests or troughs; measured in metres.
2. Frequency (ν) — Number of density oscillations per second at a fixed point; measured in hertz.
3. Time period (T) — Time for one complete oscillation; related to frequency by ν = 1/T.
4. Amplitude — Maximum change in density from the average; determines the energy carried.
5. Graph features — Crests mark maximum density (compressions) and troughs mark minimum density (rarefactions). Conclusion: These quantities together determine the wave's speed (v = λν), pitch and loudness.
Question 141: Explain how the speed of sound varies with the medium, temperature and humidity.
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Introduction: The speed of sound depends on the medium through which it propagates and on air conditions.
Key Points:
1. Dependence on medium — Sound travels fastest in solids, slower in liquids and slowest in gases.
2. Numerical comparison — About 5000 m s⁻¹ in steel, 1500 m s⁻¹ in water, 340 m s⁻¹ in air.
3. Effect of temperature — Speed in air rises from about 331 m s⁻¹ at 0 °C to 344 m s⁻¹ at 22 °C.
4. Effect of humidity — More moisture in air increases the speed of sound.
5. Independence from frequency — In most media speed depends only on the medium, not on the source frequency. Conclusion: Particles packed more closely and energetic transfer conditions make sound travel faster in some media.
Question 142: What are echo and reverberation? Explain their formation, conditions and control.
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Introduction: Echo and reverberation both arise from the reflection of sound from surfaces.
Key Points:
1. Echo formation — Sound reflects off a hard, distant surface and returns to the listener separately.
2. Condition for echo — The reflected sound must arrive at least 0.1 s after the original.
3. Minimum distance — At 340 m s⁻¹ the reflector must be at least 17 m away from the listener.
4. Reverberation — Multiple reflections arriving within 0.05 s make sound persist after the source stops.
5. Control of reverberation — Sound-absorbing panels, curtains and upholstered furniture reduce it in halls. Conclusion: Smooth hard surfaces strengthen echoes while soft porous surfaces absorb sound and clear it.
Question 143: What are ultrasonic waves? Explain their applications in different fields.
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Introduction: Ultrasonic waves are sound waves with frequencies above 20 kHz, beyond human hearing.
Key Points:
1. Medical imaging — Ultrasonography images internal organs of the body without surgery.
2. Treatment — Ultrasound breaks kidney stones into small pieces that pass out of the body.
3. Industry — Used for cleaning delicate machine parts, welding and detecting defects inside metal blocks.
4. Navigation — Sonar uses reflected ultrasonic waves to find underwater objects and ocean depth.
5. Nature's users — Bats, dolphins and whales use ultrasonic echolocation to hunt and navigate. Conclusion: Though inaudible to us, ultrasonic waves serve medicine, industry and navigation powerfully.
Question 144: Explain the principle and working of SONAR. Include a calculation.
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Introduction: SONAR (Sound Navigation And Ranging) locates underwater objects using reflected ultrasonic waves.
Key Points:
1. Transmission — A sonar device sends an ultrasonic pulse into seawater from a ship.
2. Reflection — The pulse strikes an object like a submarine or the seabed and reflects back.
3. Detection and calculation — The echo time t is measured; distance = (v × t)/2 for speed v.
4. Applications — Determines distance, direction and speed of submarines, shipwrecks and ocean depth.
5. Example — Echo returns in 0.90 s at 1530 m s⁻¹; distance = (1530 × 0.90)/2 = 688.5 m. Conclusion: Sonar adapts bat echolocation to human underwater exploration and defence.
Question 145: Describe the structure of the human ear and the process of hearing.
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Introduction: The human ear converts sound vibrations into electrical signals interpreted by the brain.
Key Points:
1. Eardrum — Sound entering the ear makes this thin membrane vibrate.
2. Amplification by bones — Tiny middle-ear bones quickly amplify the eardrum's vibrations.
3. Cochlea — Converts the amplified vibrations into electrical signals that rush to the brain.
4. Perception — The brain perceives these electrical signals as sound.
5. Direction sensing — Two ears let the brain compare arrival times and locate the sound's origin. Conclusion: This delicate chain from eardrum to cochlea makes our remarkable sense of hearing possible.
Question 146: Explain how the human ear perceives pitch and loudness, and the health hazards of noise.
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Introduction: Human perception of sound involves subjective quantities pitch and loudness, distinct from measured physical quantities.
Key Points:
1. Pitch perception — Higher frequencies are heard as shrill, high-pitch sounds like sirens.
2. Loudness perception — Larger amplitudes are heard as louder sounds, smaller ones as softer.
3. Loudness and distance — Loudness decreases as we move away from the source.
4. Noise pollution — Unwanted, harmful sound; exposure above limits affects health, sleep and hearing.
5. Protection — Hearing loss is tested with audiograms; hearing aids with microphone, amplifier and speaker help. Conclusion: Loudness is measured in decibels; normal conversation is about 60 dB and loud sounds exceed 100 dB.
Question 147: Compare longitudinal and transverse waves. Explain why sound is longitudinal. Give examples of each.
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Introduction: Mechanical waves are classified by the direction of particle vibration relative to propagation.
Key Points:
1. Longitudinal waves — Particles vibrate parallel to the direction of wave propagation.
2. Sound is longitudinal — Air particles vibrate back and forth along the direction the disturbance travels.
3. Transverse waves — Particles vibrate perpendicular to the direction of propagation.
4. Examples — Light is transverse; seismic waves may be longitudinal or transverse.
5. Common feature — Both types are mechanical if they need a medium; light needs none. Conclusion: The piston-and-tube model shows sound clearly as a longitudinal mechanical wave.
Question 148: A sound wave of wavelength 3.44 m travels through air at 344 m s⁻¹. Calculate its frequency and time period. Also find the wavelength of a sound of the same frequency travelling in water at 1500 m s⁻¹.
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Introduction: The wave equation v = λν links speed, wavelength and frequency in any medium.
Key Points:
1. Given data — Wavelength λ = 3.44 m; speed in air v = 344 m s⁻¹.
2. Frequency in air — ν = v/λ = 344/3.44 = 100 Hz.
3. Time period — T = 1/ν = 1/100 = 0.01 s.
4. Wavelength in water — λ' = v'/ν = 1500/100 = 15 m.
5. Interpretation — The same frequency gives a longer wavelength in water due to higher speed. Conclusion: Frequency depends on the source, while wavelength and speed depend on the medium.
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